Call PHP script from another with arguments and get output

Wednesday, November 4, 2015

I have a php script, let's call it one.php. This calls a second php script two.php with some arguments. Right now my code in one.php looks like this:



shell_exec("php ./two.php" . ' ' . escapeshellarg($var1) . ' '.      
escapeshellarg($var2) . ' '. escapeshellarg($var3));


This works fine (although I don't like it), but now I want to get some values that are computed in two.php.



I colud use include() or require() to get access to all the variables, but I want to use two.php in more than just one script - without having to use the same variable names in every script that calls two.php (which I had to because of the scope of the variables in include()).



My php skills are quite poor, so: Is there a way to send variables of a called script to the calling script or something like this? Or maybe another way of calling two.php.

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