Using XSL transforms to compare two nodes and then delete one

XSLT newbie - I'm trying to use XSL transforms to compare and merge XML data from two different locations.

The data currently looks like this:

<root>
  <table1>
    <product>12345</product>
    <dateCreated>2015-06-04</dateCreated>
    <dateCompleted></dateCompleted>
  </table1>
  <table2>
    <dateCreated>2015-08-28T06:34:00</dateCreated>
    <dateCompleted></dateCompleted>
  </table2>
</root>

and this is how it needs to be:

<root>
  <newtable>
    <product>12345</product>
    <dateCreated>2015-08-28T06:34:00</dateCreated>
    <dateCompleted></dateCompleted>
  </newtable>
</root>

Essentially, I need to check if /table2/dateCreated exists, and has a value, and if yes, put that node in the final XML.

The XSL file looks like this:

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  <xsl:output indent="yes" omit-xml-declaration="yes"/>
  <xsl:strip-space elements="*"/>

  <xsl:template match="node()|@*">
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>

  <xsl:template match="table1/dateCreated | table2/dateCreated">
    <xsl:if test="table2/dateCreated !=''">
      <xsl:copy>
        <xsl:apply-templates select="table2/dateCreated"/>
      </xsl:copy>
    </xsl:if>
  </xsl:template>

</xsl:stylesheet>

Obviously I'm at a loss as to what is happening - any assistance is appreciated! Thank you!